## D3dx11 43 Dll Ghost Recon Future Soldier.rar ^NEW^

D3dx11 43 Dll Ghost Recon Future Soldier.rar

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Proving that a normed space $X$ is not complete

Let $\{x_n\}$ be a Cauchy sequence in a normed space $X$ with an arbitrary norm $\|\cdot\|$. Define the function $f(x)=\|x\|^2$ and $f(y)=\frac{1}{2}\|x+y\|^2+\frac{1}{2}\|x-y\|^2$ for $x,y\in X$. Prove that $f$ is continuous and that $f(x_n)\rightarrow f(x)$ for every $x\in X$ and that $X$ is not complete.
My attempt: Since $f$ is continuous, it suffices to prove that $f$ is bounded.
\begin{align*}
|f(x_n)-f(x)|&=\frac{1}{2}\bigg|\|x_n\|^2+\|x\|^2-\|x_n-x\|^2\bigg|\\
&=\frac{1}{2}\bigg|\|x_n\|^2+\|x\|^2-\|x_n\|^2-\|x\|^2-2\|x\|^2\bigg|\\
&=\|x_n\|\bigg(\frac{1}{2}\|x_n\|+\|
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